Part I in .NET
Part V: Keeping Up with the Joneses: Maintenance and Upgrades
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=(X&), Proof We first prove the lemma. Let 6' > S and insert A = B6'cinto the premiss (here superscript c denotes complementation). This yields G{B6'c6c} F{B6'}+&. 5 We now show that B c B6'c6c, which is the same, B6"*C BC. Assume or, z E B6'c6; then 3y $ B6' with d ( z , y ) 5 6'; thus x $ B,because otherwise d(x.y) > 6'. It follows that G { B } 5 F { B 6 ' } E . Since B6 = fl,jt>6B6', the assertion of the lemma follows. We now show that dp(F,G) = 0 implies F = G. Since &>,,AE = 2,it follows from dp(F,G) = 0 that F { A } 5 G { A } and G { A } 5 F { A } for all closed sets scalars lists tuples dictionaries
Power-spectral density of (noncontinuous phase) frequency shift keying with hmod = 1.
Result (abridged):
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