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Figure 3-1: CLDC Class Hierarchy I.
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This program needs a more sophisticated data structure to help identify and then hold those unique [department, name, IP] combinations. Data structures, and references , are not part of this introductory Perl component; Perl s basics scalar, list, hash can be assembled to create many more complex structures. These are described in the perldsc section of the documentation. The perldsc reference contains cookbook style examples of lists of lists, lists of hashes, hashes of lists and what is needed here a hash of hashes. First, we need a hash indexed by department name. The data stored for each name will be a second hash; this second hash will hold IP address values indexed by machine names. The code here is essentially a copy of the perdsc cookbook code illustrating a hash of hashes. The code starts with a backticks-style system call to get the date, as illustrated above (really, you should use gmtime as documented in perlfunc). The foreach loop works on the list returned by the backticks-style system call that invokes the basic niscat report on host machines as listed in the NIS+ data tables foreach (`niscat`). Each line is split at space separators; only the first three elements are required from the line, and these are obtained by assignment to an lvalue list - ($name, $alias, $ip) = split / /. The name string must again be split, at . separators, to extract machine name
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Performance of a V-BLAST Receiver A V-BLAST receiver is, in fact, a capacityachieving scheme if powerful coding is applied [24]. However, V-BLAST receiver suffers from error propagation, which is a severe problem for uncoded systems. In fact, the earlier-detected streams may have some errors, which will affect the detection performance of the later-detected data streams.
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14. A risk assessment has determined that the losses that could be potentially incurred with the delivery system of a business may cost up to $10,000 per month. Preventive controls have been recommended that will save the company $7,000 per month, but this control will take three months to implement at a cost of $100,000 and at an ongoing cost of $1,000 per month. The business process has a life span of five years and has been in production for one year. Is the control justified A. Yes, the savings over the remaining life of the process would be $315,000, thus justifying the expense. B. No, the $3,000 per month that will be missed over the life of the process ($144,000) exceeds the cost of the control. C. Yes, the total cost of the control over the remaining process life is $145,000, while the potential loss without the control would be $480,000. D. Maybe, if the potential savings over the remaining life of the process ($315,000) minus the total cost of the control ($145,000) represents a material risk to the company s management ($170,000), management may consider implementing the control and avoiding the risk.
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As Figure 6.18 shows, PBS uses a Master host and an arbitrary number of Execution and job Submission hosts. The Master host is the central manager of a PBS cluster; a host can be con gured as a Master host and an Execution host.
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buf=malloc(sizeof(something)*user_controlled_int); for (i=0; i<user_controlled_int; i++) { if (user_buf[i]==0) break; copyinto(buf,user_buf); }
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